Viewing this, we see F is the force, k is a constant, q1 and q2 are the charges on the particles, and r is the distance between them. Let's assign both q1 and q2 the charge of +0.00005. If we hold one charge at the origin in an x-y plane, and the other we put a distance of 0.01m away on the x-axis, then we can calculate the force between them. We can infer since they are both a positive charge, they will repel each other. I have added in a friction force so the particle decelerates. The following two graphs show the change in position and the change in velocity of the particle.
If we look at the velocity vs time graph, we see the particle accelerates for for a fraction of a second, then slows down. This is because eventually, the friction force will overcome the force between the two particles and the second particle will come to a stop.
The following animation represents the motion of the second particle. Remember the first particle is at the origin, and we just assume it is next to the visible ball at the beginning of the animation.
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